Edexcel · GCSE Maths · 1MA1 · Foundation and Higher

M31 · Solids, surface area and volume

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Revision notes, worked examples and methods for solids, surface area and volume.

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Solids, views and units

  • A face is a surface, an edge is where faces meet, and a vertex is a corner. A cuboid has 6 faces, 12 edges and 8 vertices. A sphere has one curved surface and no edges or vertices.
  • A prism has a constant cross-section along its length. A pyramid has a base and triangular faces meeting at an apex. Cylinders and cones have curved surfaces, so not every face is flat.
  • A plan is the view from above; an elevation is a specified side or front view. Draw the visible outline using the given dimensions, not a perspective sketch.
    Cuboid plan and front elevationA perspective cuboid is shown beside its rectangular top view and rectangular front view. Elevations are not perspective drawings.cuboidplanfront view
    Cuboid plan and front elevation
  • Volume measures space occupied and uses cubic units; surface area totals the external surfaces and uses square units. Capacity may use litres, with 1 litre = 1000 cm3.

Volumes

  • Volume of a cuboid = lwh. Volume of a prism = cross-sectional area × perpendicular length. A cylinder has V = πr2h.
  • Worked example: A triangular prism with triangle base 4 cm, perpendicular height 3 cm and prism length 8 cm has volume ( × 4 × 3) × 8 = 48 cm3.
  • A pyramid has V = × base area × perpendicular height. A cone has V = πr2h. Slant height is not the height in these volume formulae.
  • In a right circular cone, perpendicular height h, radius r and slant height l form a right triangle: l2 = h2 + r2. Use h for volume and l for curved surface area.
    Perpendicular height and slant height in a coneA right triangle within the cone uses vertical perpendicular height h, horizontal radius r and slant hypotenuse l. Volume uses h; curved surface area uses l.hlrl² = h² + r²; h is perpendicular height
    Perpendicular height and slant height in a cone
  • A sphere has V = πr3. A hemisphere has half this volume: πr3.
  • Worked example: A cone with radius 3 cm and perpendicular height 8 cm has volume × π × 9 × 8 = 24π cm3.

Surface areas

  • Surface area of a cuboid is 2lw + 2lh + 2wh. A net helps identify every face and avoid counting a hidden internal join.
    A net with all six cuboid facesFour connected rectangles form a strip and two side faces attach to the front. Opposite matching faces are equal.topfrontbottombackleftright
    A net with all six cuboid faces
  • For a closed cylinder, total surface area is 2πr2 + 2πrh: two circular ends and one curved rectangular surface. An open-top cylinder has only one circular end.
    A closed cylinder’s net. Cylinder net with rectangle width 2πr and two circular ends
  • A cone's curved surface area is πrl, where l is slant height. Add πr2 for its circular base when finding total surface area.
  • A sphere's surface area is 4πr2. A hemisphere has curved area 2πr2, or total area 3πr2 if its circular base is included.
  • Worked example: A closed cylinder of radius 2 cm and height 5 cm has volume 20π cm3 and total surface area 8π + 20π = 28π cm2.
  • For composite volumes, add non-overlapping parts or subtract a removed region. For composite surface areas, omit faces hidden where parts join. State which surfaces the question requires.

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50 questions · Sets of 10 from the selected tier. For fractions, use / when typing; for powers, use superscripts or ^. Follow each question's answer format. These quick checks support revision; practise full written solutions and proofs too.

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Solids / views

  • Features: Faces, edges, vertices; prism constant cross-section
  • Views / units: Plan top; elevations side/front; volume cubic, area square

Volumes

  • Prism / cylinder: Cross-section × perpendicular length; cylinder πr²h
  • Pyramid / cone: Base area ×h/3; cone πr²h/3; use perpendicular h
  • Sphere: 4πr³/3; hemisphere half volume

Surface area

  • Net / cylinder: All external faces; closed cylinder 2πr²+2πrh
  • Cone: πrl curved; add πr² base; l²=h²+r²
  • Sphere / hemisphere: 4πr²; hemisphere curved 2πr², total 3πr²

Composite

  • Compare units: Cylinder r=2,h=5: V=20π cm³; SA=28π cm²
  • Joins: Add/subtract volumes; omit hidden joined surfaces

Connections

  • Solids / views → Volumes: Dimensions and views determine solid formula inputs
  • Surface area → Composite: Joined faces do not contribute external area